std::chrono::steady_clock::now(3)

NAME
std::chrono::steady_clock::now - std::chrono::steady_clock::now

Synopsis
   static std::chrono::time_point<std::chrono::steady_clock> now() (since C++11)
   noexcept;
   Returns a time point representing the current point in time.

Parameters
   (none)

Return value
   A time point representing the current time.

Example
// Run this code
 #include <chrono>
 #include <cstddef>
 #include <iomanip>
 #include <iostream>
 #include <numeric>
 #include <vector>
 volatile int sink;
 void do_some_work(std::size_t size)
 {
     std::vector<int> v(size, 42);
     sink = std::accumulate(v.begin(), v.end(), 0); // make sure it is a side effect
 }
 int main()
 {
     std::cout << std::fixed << std::setprecision(9) << std::left;
     for (auto size{1ull}; size < 10'00'00'00'00ull; size *= 100)
     {
         const auto start = std::chrono::steady_clock::now();
         do_some_work(size);
         const auto end = std::chrono::steady_clock::now();
         const std::chrono::duration<double> diff = end - start;
         std::cout << "Time to fill and iterate a vector of " << std::setw(9)
                   << size << " ints : " << diff << '\n';
     }
 }

Possible output:
 Time to fill and iterate a vector of 1 ints : 0.000006568s
 Time to fill and iterate a vector of 100 ints : 0.000002854s
 Time to fill and iterate a vector of 10000 ints : 0.000116290s
 Time to fill and iterate a vector of 1000000 ints : 0.011742752s
 Time to fill and iterate a vector of 100000000 ints : 0.505534949s