std::reverse_iterator::base(3)

NAME
std::reverse_iterator::base - std::reverse_iterator::base

Synopsis
   iterator_type base() const; (until C++17)
   constexpr iterator_type base() const; (since C++17)
   Returns the underlying base iterator. That is std::reverse_iterator(it).base() ==
   it.
   The base iterator refers to the element that is next (from the
   std::reverse_iterator::iterator_type perspective) to the element the
   reverse_iterator is currently pointing to. That is &*(rit.base() - 1) == &*rit.

Parameters
   (none)

Return value
   The underlying iterator.

Exceptions
   May throw implementation-defined exceptions.

Example
// Run this code
 #include <iostream>
 #include <iterator>
 #include <vector>
 int main()
 {
     std::vector<int> v = {0, 1, 2, 3, 4, 5};
     using RevIt = std::reverse_iterator<std::vector<int>::iterator>;
     const auto it = v.begin() + 3;
     RevIt r_it{it};
     std::cout << "*it == " << *it << '\n'
               << "*r_it == " << *r_it << '\n'
               << "*r_it.base() == " << *r_it.base() << '\n'
               << "*(r_it.base()-1) == " << *(r_it.base() - 1) << '\n';
     RevIt r_end{v.begin()};
     RevIt r_begin{v.end()};
     for (auto it = r_end.base(); it != r_begin.base(); ++it)
         std::cout << *it << ' ';
     std::cout << '\n';
     for (auto it = r_begin; it != r_end; ++it)
         std::cout << *it << ' ';
     std::cout << '\n';
 }

Output:
 *it == 3
 *r_it == 2
 *r_it.base() == 3
 *(r_it.base()-1) == 2
 0 1 2 3 4 5
 5 4 3 2 1 0

See also
   operator* accesses the pointed-to element
   operator-> (public member function)