std::experimental::erase(std::list)(3)

NAME
std::experimental::erase(std::list) - std::experimental::erase(std::list)

Synopsis
   Defined in header <experimental/list>
   template< class T, class A, class U > (library fundamentals TS v2)
   void erase( std::list<T, A>& c, const U& value );
   Erases all elements that compare equal to value from the container. Equivalent to
   c.remove_if([&](auto& elem) { return elem == value; });.

Parameters
   c - container from which to erase
   value - value to be removed

Complexity
   Linear.

Example
// Run this code
 #include <experimental/list>
 #include <iostream>
 auto show = [](const auto& container)
 {
     for (auto e : container)
         std::cout << e;
     std::cout << '\n';
 };
 int main()
 {
     std::list<int> data{1, 1, 1, 4, 1, 1, 1, 2, 1, 1, 1};
     show(data);
     std::experimental::erase(data, 1);
     show(data);
 }

Output:
 11141112111
 42

Notes
   Unlike std::list::remove, this function template accepts heterogeneous types and
   does not force a conversion to the container's value type before invoking the ==
   operator.

See also
   remove removes elements satisfying specific criteria
   remove_if (function template)
   remove removes elements satisfying specific criteria
   remove_if (public member function of std::list<T,Allocator>)
   erase_if (std::list) erases all elements satisfying a predicate from a
   (library fundamentals 2 TS) std::list
                        (function template)