skbio.tree.TreeNode.is_root¶

TreeNode.is_root()[source]¶

Returns True if the current is a root, i.e. has no parent.

State: Experimental as of 0.4.0.

Returns:	True if the node is the root
Return type:	bool

See also

is_tip(), has_children()

Examples

>>> from skbio import TreeNode
>>> tree = TreeNode.read(["((a,b)c);"])
>>> print(tree.is_root())
True
>>> print(tree.find('a').is_root())
False